What is the truth table of half subtractor?
Half Subtractor is a combinational logic circuit. It is used for the purpose of subtracting two single bit numbers. It contains 2 inputs and 2 outputs (difference and borrow).
What is meant by half subtractor?
The half subtractor is a combinational circuit which is used to perform subtraction of two bits. It has two inputs, the minuend and subtrahend and two outputs the difference and borrow out . The borrow out signal is set when the subtractor needs to borrow from the next digit in a multi-digit subtraction.
How does a half subtractor work?
The output of half subtractor is described in two columns. One will signify the difference bit, and another will signify the borrow bit. To derive the truth table, just use the EX-OR operation of two inputs for generating difference and NOT followed by AND operation for generating the borrow bit.
How to design a half subtractor using CMOS?
This paper presents designing of Half Subtractor using basic gates which are drawn by conventional CMOS and Pass Transistor Logics based on 45nm technology .
How to solve the half subtractor truth table?
The half subtractor truth table explanation can be done by using the logic gates like EX-OR logic gate and AND gate operation followed by NOT gate. Solving the truth table using K-Map is shown below. The Boolean expression of the half subtractor using truth table and K-map can be derived as
What is the borrow output of a half subtractor circuit?
Conventional Half-Subtractor Circuit A conventional Half-subtractor circuit is a combinational circuit that can be used to subtract one binary digit from another to produce a Difference output and a Borrow output. The Borrow output here specifies whether a ‘1’ has been borrowed to perform the subtraction.
When to use a half subtractor In math?
Figure below shows the block diagram of half subtractor. Half-subtractor is used to subtract one binary digit from another to give DIFFERENCE output and a BORROW output. The truth table of a half-subtractor is shown in figure below. 1) When the inputs minuend (A) =0, Subtrahend (B) =0 then the difference (D) = 0 and Borrow out (Bo) =0